![]() † † margin: y y x - 2 - 1 1 2 - 2 - 1 1 2 50 water line not to scale d ( y ) = 50 - y Figure 6.5.8: Measuring the fluid force on an underwater porthole in Example 6.5.4. The truth is that it is not, hence the survival tips mentioned at the beginning of this section. This is counter-intuitive as most assume that the door would be relatively easy to open. Most adults would find it very difficult to apply over 500 lb of force to a car door while seated inside, making the door effectively impossible to open. Next to the lake, a glacier with the same volume as the floating ice sits on land. 3 ¯, - 2.25 ) ( 0, - 2.25 ) ( 0, 0 ) y y x Figure 6.5.7: Sketching a submerged car door in Example 6.5.3. Why is a force exerted by a static fluid on a surface always perpendicular to the surface Imagine that in a remote location near the North Pole, a chunk of ice floats in a lake. Using the weight-density of water of 62.4 lb/ft 3, we have the total force as ![]() ![]() We adopt the convention that the top of the door is at the surface of the water, both of which are at y = 0. Its length is 10 / 3 ft and its height is 2.25 ft. A cylindrical storage tank has a radius of 2 ft and holds 10 ft of a fluid with a weight-density of 50 lb/ft. SolutionThe car door, as a rectangle, is drawn in Figure 6.5.7. We use this definition to find the force exerted on a horizontal sheet by considering the sheet's area.
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